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A transistor is operated in common emitter configuration at constant collector voltage $V_{c}$ = 1.5 V such that a change in the base current from 100 µA to 150 µA produces a change in the collector current from 5 mA to 10 mA. The currentgain ( $β$ )is

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Detailed Solution

AC current gain $β$ is defined as the ratio of the change in collector to the change in base current at constant collector voltage,

$β = {(\frac{∆ i_{C}}{∆ i_{B}})}_{Vc} Given ∆ i_{C} = 10 mA - 5 mA = 5 mA ∆ i_{B} = 150 μA - 100 μA = 50 μA ∴ β = \frac{5 mA}{50 \times 10^{- 3} mA} = 100$

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