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Q.

A transistor is used in an amplifier circuit in common emitter mode. If the base current changes by 100 $μ A$ , it brings a change of 10 mA in collector current. If the load resistance is $2 kΩ$ and input resistance is $1 kΩ$ , the value of power gain is $x \times 10^{4}$ . The value of x is _________ .

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Detailed Solution

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$\begin{array}{l} {Δi}_{B} = 100 μA β = \frac{{Δi}_{C}}{{Δi}_{B}} \\ {Δi}_{C} = 10 mA \\ power = β^{2} \times \frac{R_{0}}{R_{in}} \\ Power = {(\frac{10}{0 .1})}^{2} \times \frac{2}{1} \\ Power = 100 \times 100 \times 2 \\ Gain = 2 \times 10^{4} \end{array}$

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