A transition metal M forms a volatile chloride which has a  vapour density of 94.8. If it contains 74.75% of chlorine the  formula of the metal chloride will be  

74.75% of chlorine means 74.75g chlorine is present
 in 100g of metal chloride.   
Weight of metal = 100g — 74.75g 
$=25.25\mathrm{g}$
Equivalent weight 
$$\begin{gathered} \text{=}\frac{ \mathrm{weightofmetal} }{ \mathrm{weightofchlorine} }\times 35.5 \\ =\frac{25.25}{74.75}\times 35.5=12 \\ \mathrm{Valencyofmetal} =\frac{2\times \mathrm{V}.\mathrm{D}. }{ \mathrm{Equivalentwt}.\mathrm{ofmetal} +35.5} \\ =\frac{2\times 94.8}{12+35.5}=4 \\ \therefore \text{ Formula of compound }={MCl}_4 \end{gathered}$$