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A transmitting antenna is at height of 40m and the receiving antenna is at a height of 60m. The maximum distance between then for satisfactory communication is nearly

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50 km

25 km

224 km

answer is C.

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Detailed Solution

$d = \sqrt{2 R h_{t}} + \sqrt{2 R h_{r}}$
$\begin{array}{l} = \sqrt{2 \times 6.4 \times 10^{6} \times 240} + \sqrt{2 \times 64 \times 10^{6} \times 60} \\ = 50 \times 10^{3} = 50 k m \end{array}$

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