Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A transparent film of refractive index, 2.0 is coated on a glass slab of refractive index, 1.45. What is the minimum thickness of transparent film to be coated for the maximum transmission of green light of wavelength 550 nm?

[Assume that the light is incident nearly perpendicular to the glass surface.]

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

94.8 nm

b

137.5 nm 

c

275 nm

d

68.7 nm

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Step 1: Condition for Maximum Transmission (Minimum Reflection)

For a thin film on a denser medium, the condition for destructive interference (so that light does not reflect and is mostly transmitted) is:

2tn=mλ2 t n = m \lambda

For minimum thickness, we take m = 1:

2tn=λ2 t n = \lambda

Step 2: Given Data

Refractive index of the film: n=2.0n = 2.0

Refractive index of glass: nglass=1.45n_{\text{glass}} = 1.45 (not needed for calculation)

Wavelength of green light in air: λ=550\lambda = 550nm

Step 3: Calculate the Minimum Thickness

Rearranging the equation:

t=λ2nt = \frac{\lambda}{2n}

Substituting values:

t=5502×2.0t = \frac{550}{2 \times 2.0}

 t=5504=137.5 nmt = \frac{550}{4} = 137.5 \text{ nm}

 

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon