A transparent glass plate of thickness 0.5 mm and refractive index 1.5 is placed infront of one of the slits in a double slit experiment. If the wavelength of light used is 6000 A0, the ratio of maximum to minimum intensity in the interference pattern is 25/4. Then the ratio of intensity of transmitted light to that of the light incident on thin transparent glass plate is

The ratio of intensity of light transmitted (I2) to the incident (I1) on thin transparent film is

A transparent glass plate of thickness 0.5 mm and refractive index 1.5 is placed infront of one of the slits in a double slit experiment. If the wavelength of light used is 6000 A0, the ratio of maximum to minimum intensity in the interference pattern is 25/4. Then the ratio of intensity of transmitted light to that of the light incident on thin transparent glass plate is

The ratio of intensity of light transmitted (I2) to the incident (I1) on thin transparent film is

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A transparent glass plate of thickness 0.5 mm and refractive index 1.5 is placed infront of one of the slits in a double slit experiment. If the wavelength of light used is 6000 $\overset{0}{A}$ , the ratio of maximum to minimum intensity in the interference pattern is 25/4. Then the ratio of intensity of transmitted light to that of the light incident on thin transparent glass plate is

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7 : 3

3 : 7

9 : 7

9 : 49

answer is B.

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Detailed Solution

$\frac{{{I_{\max }}}}{{{I_{\min }}}} = \frac{{25}}{4} \Rightarrow \$ $\left ( \frac{\sqrt{I_1}+\sqrt{I_2}}{\sqrt{I_1-\sqrt{I_2}}} \right )^2=\frac{25}{4}$

$\frac{{\sqrt {{I_1}} + \sqrt {{I_2}} }}{{\sqrt {{I_1}} - \sqrt {{I_2}} }} = \sqrt {\frac{{25}}{4}} = \frac{5}{2} \Rightarrow \frac{{\sqrt {{I_1}} }}{{\sqrt {{I_2}} }} = \frac{{5 + 2}}{{5 - 2}} = \frac{7}{3}\$