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A transverse progressive wave on a stretched string has a velocity of 10 ms^-1 and a frequency of 100 Hz. The phase difference between two particles of the string which are 2.5 cm apart will be

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$\frac{π}{2}$

$\frac{π}{4}$

$\frac{π}{8}$

$\frac{3 π}{8}$

answer is D.

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Detailed Solution

$v = nλ \Rightarrow λ = 10 cm$
Phase difference $\frac{2 π}{λ} \times$ Path difference = $\frac{2 π}{10} \times 2 .5 = \frac{π}{2}$

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