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Q.

A transverse progressive wave on a stretched string has a velocity of 10 ms-1 and a frequency of 100 Hz. The phase difference between two particles of the string which are 2.5 cm apart will be

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a

π8

b

π4

c

3π8

d

π2

answer is D.

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Detailed Solution

v=nλ⇒λ=10  cm 
Phase difference 2πλ×Path difference = 2π10×2.5=π2

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