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Q.

A transverse wave is passing through a light string shown in the figure. The equation of wave is y=Asinωt−kx. The area of cross-section of string is A and density is ρ. The hanging mass is

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a

ρAω2k2g

b

ωkg

c

Aω

d

k2gω

answer is C.

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Detailed Solution

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Vω=ωk=TAρ

⇒ω2k2=mgAρ

⇒ω2Aρk2g=m

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