Q.

A transverse wave is represented by y=2 sin (ωtkx) cm. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity, will be ;

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a

2

b

2π

c

4π

d

π

answer is A.

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Detailed Solution

y=2 sin (ωtkx)

Maximum particle velocity=A ω

Wave velocity=ωk

ωk=k=1A=2πλλ=2πA=4πcm

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