A Transverse wave propagating on a stretched string of linear density $3\times {10}^{-4}Kg{m}^{-1}$ is represented by the equation y = 0.2 sin (1.5x + 60t) where, x is in metres and t is in seconds. The tension in the string (in newtons)

Equation of wave, $y=0.2\sin (1.5x+60t)$

Comparing with standard equation, we get

$y=A\sin (Kx+\omega t)=k=1.5$ and $\omega$ =60

Velocity of wave, $V=\frac{\omega }{k}=\frac{60}{1.5}=40m/s$

$V=\sqrt{\frac{T}{m}}$

Where m is linear density and T is tension in the string

So, $T=V^{2}m={\left(40\right)}^2\times 3\times {10}^{-4}=0.48N$