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A transverse wave propagating on a stretched string of linear density $3 \times 10^{- 4} kg m^{- 1}$ is represented by the equation y = 0.2 sin (1.5x + 60t) where ‘x’ is in metres and ‘t’ is in seconds. The tension in the string (in newtons) is

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1.80

0.24

0.48

1.20

answer is B.

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Detailed Solution

$V = \frac{ω}{K} = \sqrt{\frac{T}{μ}}$

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