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A travelling microscope is focused on a mark at the bottom of a beaker and then it is raised by 2 cm. The depth of water poured in the beaker so that the same mark may be focused again $(μ = \frac{4}{3})$

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8 cm

4 cm

2 cm

1 cm

answer is A.

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Detailed Solution

Shift = 2cm

$μ = \frac{4}{3}$

$shift = (1 - \frac{1}{μ}) t$

$2 = (1 - \frac{1}{\frac{4}{3}}) t$

$t = 8cm$

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