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Q.

A travelling microscope is used to determine the refractive index of a glass slab. If 40 divisions are there in 1 cm on main scale and 50 Vernier scale divisions are equal to 49 main scale divisions, then least count of the travelling microscope is ______×10^–6 m.

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answer is 5.

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Detailed Solution

50 VSD = 49 MSD
$1 VSD = \frac{49}{50} MSD$
Least count = 1 MSD – 1 VSD
$= (1 - \frac{49}{50}) MSD = \frac{1}{50} MSD$
$1 MSD = \frac{1}{40} cm$
Least count $= \frac{1}{50 \times 40} cm$
$\begin{array}{l} = \frac{1}{2000} cm = \frac{1}{2} \times 10^{- 5} m \\ = 0 .5 \times 10^{- 5} m \\ = 5 \times 10^{- 6} m \end{array}$

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A travelling microscope is used to determine the refractive index of a glass slab. If 40 divisions are there in 1 cm on main scale and 50 Vernier scale divisions are equal to 49 main scale divisions, then least count of the travelling microscope is ______×10–6 m.