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A triangular shaped wire carrying 10A current is placed in a uniform magnetic field of 0.5T, as shown in figure. The magnetic force on segment CD is (Given BC = CD = BD = 5 cm).

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0.126 N

0.245 N

0.312 N

0.216 N

answer is C.

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Detailed Solution

$F_{m} (CD) = {BIl}_{eff} = 0.5 \times (10) \times (5 \sin 60 \times 10^{- 2}) = 0.216 N$

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