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A trivalent metal has mass % of metal in its superoxide equal to 36%. Calculate approximate specific heat capacity of metal.

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$\frac{54}{6.4} Cal / {gm}^{\circ} C$

$\frac{6.4}{54} Cal / {gm}^{\circ} C$

$\frac{6.4}{18} Cal / {gm}^{\circ} C$

$\frac{18}{6.4} Cal / {gm}^{\circ} C$

answer is B.

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Detailed Solution

$M {(O_{2})}_{3}$ (Since, superoxid is ${O_{2}}^{-_{}}$

$Specific heat = \frac{6.4}{Atomic weight}$

$\frac{36}{100} \times (M + 96) = M$

$\Rightarrow M = 54$

So, specific heat $= \frac{6 \cdot 4}{54}$

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