A (trolley + child) of total mass 200 kg is moving with a uniform speed of 36 km/h on a frictionless track. The child of mass 40 kg starts running on the trolley from one end to the other (10 m away) with a speed of $10 m s^{- 1}$ relative to the trolley in the direction of the trolley’s motion and jumps out of the trolley with 10m/s relative to trolley at that moment. What is the final speed of the trolley?(in m/s)

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answer is 8.

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Detailed Solution

Applying momentum conservation
$200 \times 10 = 40 (v + 10) + 160 v$
$v = 8 m / s$

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