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A trolley of mass 360 kg is lying on a horizontal frictionless surface. A man of mass 40 kg runs with uniform speed on the trolley by a distance of 2m in 0.5 second. What is the velocity of the trolley relative to earth?

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0.8 m/s

0.4 m/s

1.6m /s

2.2m/s

answer is B.

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Detailed Solution

From the question,

$Man + Trolley System :$

$V_{com} = 0$

$\Rightarrow 0 = {Mv}_{t / e} + {mv}_{m / e}$

$\Rightarrow v_{m / t} = \frac{2}{\frac{1}{2}} = 4$

$v_{m / t} = v_{m / e} - v_{t / e}$

$v_{m / e} = v_{m / t} + v_{t / e}$

${Mv}_{t / e} + m (v_{m / t} + v_{t / e}) = 0$

$(M + m) v_{t / e} + {mv}_{m / t} = 0$

$v_{t / e} = \frac{- {mv}_{m / t}}{M + m} = \frac{- 40 \times 4}{400} = - 0.4 m / s$

Hence the correct answer is 0.4m/s

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