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A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration ( $in m / s^{2}$ ) changes from (g=10 m/s²)

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An Intiative by Sri Chaitanya

3.33 to 6

2.5 to 3.75

4 to 5

2.33 to 4.2

answer is B.

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Detailed Solution

initially mass on the table is 6 kg and mass hanging 2 kg so acceleration of the system is $\frac{2 g}{8} = \frac{20}{8} = 2.5$

finally mass on the table is 5 kg and mass hanging 3 kg so acceletation of the system is $\frac{3 g}{8} = \frac{30}{8} = 3.75$

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