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Q.

A trophy awarded to the best student in the class is in the form of a solid cylinder mounted on a solid hemisphere with the same radius and is made from some metal. The diameter of the hemisphere is 21 cm   and the total height of the trophy is 24.5 cm  . What is the weight of the metal used in making the trophy, if the weight of 1  cm 3   of the metal is 1.2 g  taking π= 22 7  ?


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a

8.731 kg  

b

7.816kg

c

7.516kg

d

6.416kg 

answer is A.

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Detailed Solution

Given that the diameter of the hemisphere is 21 cm  , the total height of the trophy is 24.5 cm   and the weight of 1  cm 3   metal is 1.2 g  .
We have the following formulae,
Volume of cylinder = π r 2 h  
Volume of hemisphere = 2 3 π r 3  
The total volume of the trophy is the sum of the Volume of cylinder and the Volume of Hemisphere.
Height of the cylinder will be,
24.5-10.5
=14
Volume of trophy,
=π r 2 h+ 2 3 π r 3   =π r 2 h+ 2 3 ×r   = 22 7 × 21 2 2 × 14+ 2 3 ×10.5   =7276.5  cm 2  
The total weight of the trophy will be,
=7276.5 ×1.2   =8731.8g                                     (1kg=1000g)
8.731 kg  
Thus, the total weight of the trophy is 8.731 kg  .
Therefore the correct option is 1.
 
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