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A truck is moving on a straight road with a uniform velocity of 10 m/s. An obstacle is observed at a distance of 50 m. The driver of the truck applies brakes which produce retardation of 2 m/s². Find what is the position of the truck at t = 6 sec.

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15 m

20 m

25 m

35 m

answer is C.

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Detailed Solution

v = u - at

v = 0; u = 10; a = –2 m/s²

The truck will stop at t = 5 sec.

Therefore, $s = ut + \frac{1}{2} {at}^{2}$

$s = 10 \times 5 + \frac{1}{2} \times (- 2) \times 5^{2} = 25 m$

Hence truck will stop at 25 m, but time will not stop.

Therefore, at t = 6 sec, the position of the object will be x = 25 m.

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