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A truck of mass $1000 kg$ is moving with a velocity of $10 m / s$ and is acted upon by a forward force of $1000 N$ due to the engine and retarding force of $500 N$ . What will be the velocity after $10 \sec$ ?

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10 m / s

15 m / s

20 m / s

Zero

answer is B.

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Detailed Solution

A truck of mass

1000 kg

is moving with a velocity of

10 m / s

and is acted upon by a forward force of

1000 N

due to the engine and retarding force of

500 N

. The velocity after

10 \sec

will be

15 m / s

.
Mass

m = 1000 kg

The initial velocity of the bike

u = 10 m / s

Time

t = 10 s

Retarding force

f = 500 N (in backward direction)

Applied force

F = 1000 N (in forward direction)

In order to find the velocity we need to find the value of the acceleration first,
The acceleration of the bike is in the forward direction. Therefore, using

F = ma

a = \frac{F - f}{m}

\Rightarrow a = \frac{1000 - 500}{1000}

\Rightarrow a = 0.5 m s^{- 2}

Now using

v = u + at

, where

v

represents final velocity

\Rightarrow v = 10 + 0.5 \times 10

\Rightarrow v = 15 m / s

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