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A truck which is moving at $4 m / s$ of mass $500 kg$ collides with another truck of mass $1500 kg$ moving in the same direction at $2 m / s$ . Combined velocity is [[1]] $m / s$ just after the collision if they move off together.

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Detailed Solution

A truck which is moving at

4 m / s

of mass

500 kg

collides with another truck of mass

1500 kg

moving in the same direction at

2 m / s

. Combined velocity is

2.5 m / s

just after the collision if they move off together.
Given
Mass of the first truck,

m_{1} ​ = 500 kg

Speed of the first truck,

u_{1} ​ = 4 m / s

Mass of the second truck,

m_{2} = 1500 kg

Speed of the second truck,

u_{2}

= 2 m / s

Combined mass of both trucks,

m = 1500 + 500

= 2000 kg

To find:
Combined velocity

v

Acc. to the law of conservation of momentum

\Rightarrow m_{1} u_{1} + m_{2} u_{2} = mv

\Rightarrow 500 \times 4 + 1500 \times 2

= 2000 \times v

\Rightarrow v = \frac{2000 + 3000}{2000}

\Rightarrow v = 2.5 m / s

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