A tube is inverted in a mercury vessel as shown in figure. If pressure P is increased, then

List I List II
A) Height h P) will increase
B) Pressure at O Q) will decrease
C) Pressure at 1 cm above O R) will remain same
D) Pressure at 1 cm below O S) will be zero
T) can't be determined

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$A \to Q; B \to R; C \to P; D \to S$

$A \to Q; B \to R; C \to R; D \to R$

$A \to R; B \to Q; C \to R; D \to R$

$A \to S; B \to R; C \to Q; D \to P$

answer is B.

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Detailed Solution

Pressure at O= $P + ρ g h$ = Atmospheric pressure
If height increases, P will decrease as atmospheric pressure is constant.

Pressure at O=Atmospheric pressure = constant
Pressure at 1 cm above O = $P_{0} - ρ g (1)$ , this is independent of pressure P.

Pressure at 1 cm below O = $P_{0} + ρ g (1)$ , this is also independent of pressure P.

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