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A tube is mounted so that it’s base is at height ‘h’ above the horizontal ground. The tank is filled with water to a depth h. A hole is punched in the side of the tank at depth y below water surface. Then the value of y so that the range of emerging stream would be maximum is

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h/4

h/2

3h/4

answer is A.

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Detailed Solution

$R tobe maximum, \frac{dR}{dy} = 0, which gives y = h$

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