Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A tuning fork A of unknown frequency produces 5 beats/s with a fork of frequency 340Hz. When fork A is filed, the beat frequency decreases to 2 beats/s/ What is the initial frequency of fork A before filing ?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

342 Hz

b

345 Hz

c

335 Hz

d

338 Hz

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Initially beat frequency = 5 Hz
so, ρA=340±5=345 Hz, or 335 Hz
After filing frequency increases slightly
so, new value of frequency of  A>ρA
Now, beat frequency = 2 Hz
⇒ new ρA=340±2=342 Hz , or 335Hz
hence, original frequency of A is ρA=335 Hz

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring