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A tuning fork of known frequency 256 Hz makes 5 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

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256 +2Hz

256 + 5 Hz

256+2Hz

256-2Hz

answer is D.

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Detailed Solution

We know that the frequency of a vibrating string
$n = \frac{1}{2 l} \sqrt{(\frac{T}{m})} or n \propto \sqrt{T} Frequency of piano string may be 2 SS + 5 or 256 - 5 . Before increasing the tension, the frequency of piano was 256 - 5 = 251 H 2$

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