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Q.

A tuning fork of known frequency 256 Hz makes 5 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was 

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a

256 + 5 Hz

b

256 + 2Hz

c

256 – 2 Hz

d

256 – 5Hz

answer is D.

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Detailed Solution

Suppose nP = frequency of piano = ?  (nPT)
nf = Frequency of tuning fork = 256 Hz
x = Beat frequency = 5 bps, which is decreasing (52) after clanging the tension of piano wire 
Also, tension of piano wire is increasing so nP
Hence nP– nf = x             Wrong 
          nf – nP= x             Correct 
 nP = nf – x = 256 – 5 Hz.

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A tuning fork of known frequency 256 Hz makes 5 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was