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A tuning fork produces 4 beats per sec with one fork of frequency 288 cps. A little wax is placed on the unknown fork and it produces 2 beats per second. The frequency of unknown fork is

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286 cps

294 cps

288 cps

292 cps

answer is B.

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Detailed Solution

n_B maybe 288 + 4 = 292 Hz or 288 – 4 = 284 Hz
n_B is waxed beats decreased so it is 292 Hz

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