AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A tunnel is dug along a chord of earth at a perpendicular distance $\frac{R}{2}$ from the earth's centre. The wall of the tunnel may be assumed to be frictionless. A particle is released from one end of the tunnel. The pressing force by the particle on the wall and the acceleration of the particle vary with $x$ (distance of the particle from the centre) as

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

A tunnel is dug along a chord of the earth at a perpendicular distance R/2 from the earth's centre. The wall of the tunnel may be assumed to be frictionless. A particle

answer is B, C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

When the distance of the particle from the centre is $x, E_{g} = \frac{G M}{R^{3}} \cdot x$

$∴ F = \frac{G M m}{R^{3}} \cdot x$

$∴ N = F \sin θ$

$= \frac{G M m}{R^{3}} \cdot x \frac{R / 2}{x}$

$= \frac{G M m}{2 R^{2}}$

$∴ N$ is constant and independent of $x$ . Tangential force is

$F_{t} = F \cos θ = \frac{G M m x}{R^{3}} \times \frac{\sqrt{x^{2} - \frac{R^{2}}{4}}}{x}$

$∴$ Acceleration is $a = \frac{F_{t}}{m} = \frac{G M}{R^{3}} \cdot \frac{1}{2} \sqrt{4 x^{2} - R^{2}}$

At $x = \frac{R}{2}, a = 0$

and at $x = R, a = \frac{\sqrt{3}}{2} \cdot \frac{G M}{R^{2}}$

As, $x$ increases, then $a$ increases.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!