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A turn has a radius of $10 m$ . If a vehicle goes round it at an average speed of $18 km / h$ , what should be the proper angle of banking?

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$\cos^{- 1} (\frac{1}{2})$

$\tan^{- 1} (\frac{1}{4})$

$\sin^{- 1} (\frac{1}{5})$

$\tan^{- 1} (\frac{2}{6})$

answer is B.

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Detailed Solution

$v = \frac{18 \times 5}{18} = 5 m / s$

$\tan θ = \frac{v^{2}}{R g} = \frac{(5)^{2}}{10 \times 10} = \frac{1}{4}$

$∴ θ = \tan^{- 1} (\frac{1}{4})$

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