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A TV set picture tube shoots out a beam of electrons. The current due to this beam is $5 mA$ .

Then, which of the following is the total number of electrons that will strike the TV screen every second?

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3.55 \times 1 0^{16}

3.65 \times 1 0^{16}

3.25 \times 1 0^{16}

3.35 \times 1 0^{16}

answer is C.

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Detailed Solution

A TV set picture tube shoots out a beam of electrons. The current due to this beam is

5 mA

.
Then, the total number of electrons that will strike the TV screen every second is

3.25 \times 1 0^{16}

.
First of all, let’s find the amount of charge in this beam of electrons which
can be found by using the formula:

Q = I \times T

Where

Q

is a charge and its S.I unit is

Coulomb

I

is the amount of current in

Ampere

T

is the time in

seconds

.
Therefore, substituting all the values from the question, we get,

q = 5 mA = 5 \times 1 0^{- 3} A

As the charge is always quantized in nature, the net charge of the body can be expressed as the integral multiples of the basic unit of charge. Mathematically, it can be written as:

q = N \times E

Where

N

is the number of electrons. It represents an integer and cannot be a fraction.

E

is the charge on one electron which is equal to

1.6 \times 1 0^{- 19}

C.
Therefore,

N = \frac{q}{E}

⇒

N = \frac{5 \times 1 0^{- 3} \times 1}{1.6 \times 1 0^{- 19}}

∴ n = 3.25 \times 1 0^{16}

Hence,

3.25 \times 1 0^{16}

electrons strike the T.V screen in a

minute .

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