A Tv tower has height of 100 m. how much population is covered by the TV broadcast, if the average population density around the tower is 1000 km? given, radius of the earth $=6.37\times {10}^{6}m$

Here, $h=100m,$$R=6.37\times {10}^{6}m$

Radius of circle within which transmission can be viewed,

$d=\sqrt{2hR}=\sqrt{2\times 100\times 6.37\times {10}^6}=3.57\times {10}^{4}m$

Area in which transmission can be viewed, $A=\pi d^2=\pi \times {\left(3.57\times {10}^4\right)}^2$

$=4.04\times {10}^9{m}^2=4\times {10}^{3}k{m}^2$

Population density = $1000k{m}^{-2}$

Therefore, population covered by transmission

 $=4\times {10}^3\times 1000=4\times {10}^6$