A typical dihybrid cross is done between a pea plant having round and yellow seeds with a pea plant having green and wrinkled seed. What is the probability of the seeds having wrinkle phenotype in the F₂ generation.

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$\frac{12}{16}$

$\frac{3}{4}$

$\frac{6}{16}$

$\frac{1}{4}$

answer is B.

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Detailed Solution

A typical dihybrid cross is done between a pea plant having round and yellow seeds with a pea plant having green and wrinkled seed. The F₂ generation will have the ratio 9 (round and yellow):3(round and green):3 (wrinkled and yellow):1(wrinkled and green). Therefore, the probability of getting wrinkled seeds is $\frac{(3 + 1)}{(9 + 3 + 3 + 1)} = \frac{4}{16} = \frac{1}{4}$