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Q.

A uniform chain of length L and mass M is lying on a smooth horizontal table and $\frac{2}{3}$ of its length is hanging down over the edge of the table. The work done by a horizontal force in slowly pulling the hanging part on to the table is

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a

$\frac{M g L}{3}$

b

MgL

c

$\frac{2 M g L}{9}$

d

$\frac{M g L}{9}$

answer is D.

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Detailed Solution

Mass of the hanging part = $\frac{2 M}{3}$
Depth of the COM of hanging part = $\frac{L}{3}$
Work done = $(\frac{2 M}{3}) (g) (\frac{1}{3})$

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A uniform chain of length L and mass M is lying on a smooth horizontal table and 23 of its length is hanging down over the edge of the table. The work done by a horizontal force in slowly pulling the hanging part on to the table is