A uniform conducting wire ABC has a mass of 10 g. A current of 2 A flows through it. The wire is kept in a uniform magnetic field B = 2 T. The acceleration of the wire will be
 

The given curved wire can be treated as a straight wire as shown
 

Force acting on the wire AC,  

= $F=Bil=2\times 2\times 3\times {10}^{-2}$

$12\times {10}^{-2} \mathrm{N}$

  along positive y-axis.
So acceleration of wire 

$=\frac{F}{m}=\frac{12\times {10}^{-2}}{10\times {10}^{-3}}=12 \mathrm{m}/{\mathrm{s}}^2$