A uniform conductor of resistance R is cut into 20 equal pieces. Half of them are joined in series and the remaining half of them are connected in parallel. If the two combinations are joined in series, then the effective resistance of all the pieces is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$R$

$\frac{R}{2}$

$\frac{101 R}{200}$

$\frac{201 R}{200}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The effective resistance of the series combination = $10 . \frac{R}{20} = \frac{R}{2}$

The effective resistance of the parallel combination = $\frac{1}{10} . \frac{R}{20} = \frac{R}{200}$

So the series combination of these will have an effective resistance $= \frac{R}{2} + \frac{R}{200} = \frac{101 R}{200}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE