A uniform disc of mass m and Radius R is rolling on a flat rough surface, without slipping at bottom. If ‘t’ is the thickness of the disc and $\sigma$  is the Breaking stress of the material of the disc, then

Maximum Normal force of Interaction between left half and right half of the disc would be, $\frac{2mR{w}^2}{3\pi }$ .

Maximum angular speed at which material ruptures varies with $\sigma$  as,  $\omega \propto {\sigma }^2$

Point of application of Normal force of interaction does not passes through center of the disc.

Maximum angular speed and Breaking stress of the material are related as  ${\omega }^2\propto \sigma$