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A uniform disc of mass ‘m’ and radius ‘r’ rotates along an axis passing through its center of mass and normal to its plane. An un-stretchable light rope is wound on the disc. Tangential acceleration of a point P on peripheral of the disc when a uniform force F is applied on the rope is

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F/2m

2Fmr

F/m

2F/m

answer is D.

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Detailed Solution

$rF = Iα \Rightarrow rF = (\frac{{mr}^{2}}{2}) \frac{a}{r} \Rightarrow a = 2 F / m$

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