Q.

A uniform disc of radius r and mass m is charged uniformly with the charge q. This disc is placed flat on a rough horizontal surface having coefficient of friction μ. A uniform magnetic field is present in a circular region (a > r) but varying as kt3 as shown in figure. Find the time in second after which the disc begins to rotate. (Given r = 1m, m = 18 kg, q = 1C, μ=0.1, K = 4, g = 10 m/s2)

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answer is 2.

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Detailed Solution

 E=x2dBdt
 E=3Kxt22
 dt=3Kxt22×2πxdxπr2q.x
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τ=3Kt2qr20rx3dx 
τ=3Kq.t24  …..(i)
torque due to friction force
dτ=μdmgx 
τ=2μgqmr20rx2dx=23μmgr …..(ii)
3Kq.t2r24=23μmgr 
t=8μmg9Kqr=2 seconds

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