A uniform disc of radius R rolls without slipping on a rough horizontal surface. At an instant, A is the lowest particle of the disc and C is the centre of disc. Then the location of particles on the disc at that instant, whose normal acceleration is zero, can be:

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

Centre C of the disc

All particles on circle drawn on the disc plane with AC as diameter except A.

All points on arc of a circle drawn with centre at A on disc and having radius R/2

No particle on disc has zero normal acceleration

answer is A, B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Take a point P on disc at a distance x from A, such that AP makes an angle  with vertical diameter of disc. Then the normal acceleration of P is $ω^{2} x - ω^{2} R \cos θ$ towards A. Then the locus of points whose normal acceleration is zero are given by $x = R \cos θ$ . This is a circle with diameter AC