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Q.

A uniform electric field of magnitude 325 V/m is directed in the negative y direction in figure. The coordinates of point A are (-0.2 m, -0.3 m) and those of point B are (0.4 m, 0.5 m). Calculate the potential difference V_B - V_A (in volts), along the path shown in the figure

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answer is 260.

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Detailed Solution

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The potential difference between two points A and B in electric field as, $V_{B} - V_{A} = - \int_{A}^{B} \vec{E} \cdot \vec{d} r$
Here the electric field is constant, here we can write the potential difference between
points A and B as
$V_{B} - V_{A} = - [E_{x} (x_{B} - x_{A}) + E_{y} (y_{B} - y_{A})] =$ $= [(- 325) {(0.5) - (- 0.3)}] = 325 \times 0.8 = 260 V$

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