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A uniform electric field of magnitude $5 x 10^{3} N / C$ is directed along the negative x-direction. Co-ordinates of point A in the Fig. 2.134 are (-40 cm,+ 20 cm) and those of point Bare (20 cm, -60 cm). Potential difference between A and B, i.e., $V_{A} - V_{B}$ along the arc of a circle of radius 2 m is :

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-2400 V

-5000 V

-3000 V

2400 V

answer is D.

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Detailed Solution

$V_{A} - V_{B} = ∆ V = - \vec{E} . ∆ \vec{r}$

$= - (- 5 x 10^{3} \hat{j}) . (- 0.6 \hat{i}) = - 3000 volt$

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