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Q.

A uniform heavy rod of weight 10 kg ms–2, cross-sectional area 100 cm2 and length 20cm is hanging from a fixed support. Young modulus of the material of the rod is 2 × 1011Nm–2. Neglecting the lateral contraction, find the elongation of rod due to its own weight 
 

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a

5 × 10–8 m 
 

b

5 × 10–10 m 
 

c

4 × 10–8 m 
 

d

2 × 10–9 m 
 

answer is B.

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Detailed Solution

image

We know that,

∆l=WL2AY=10×12×5×100×10-4×2×1011=5×10-10m

Hence the correct answer is 5×10-10m.

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