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Q.

A uniform hollow sphere of radius 30 cm is released from rest on a rough inclined plane. The friction is sufficient to prevent any slipping. Find the angular velocity (in rad/s) of the sphere, when its center of mass descends through a vertical height of 3 cmg=10 m/s2

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answer is 2.

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Detailed Solution

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Loss in PE=gain in KE

mgh=12mv2+12Iω2 mgh=12m(ωr)2+12(23mr2)ω2 m×10(3100)=m56×(30100)2ω2ω=2rad/s

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