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A uniform horizontal metre scale of mass m is suspended by two vertical strings attached to its two ends. A body of mass 2m is placed on the 75-cm mark. The tensions in the two strings are in the ratio

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3 : 4

2 : 3

1 : 3

1 : 2

answer is A.

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Detailed Solution

$T_{1} + T_{2} = 3 m g$

Taking torque about zeroeth end.

$T_{2} \times 100 = m g \times 50 + 2 m g \times 75$

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