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A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10 π rad s^–1 about an axis through its centre and perpendicular to the disc. What is the protential difference developed between the axis of the disc and the rim ? (π = 3.14)

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0.5024 V

0.1256 V

0.2512 V

0.0628 V

answer is C.

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Detailed Solution

B = 0.4 T
r = 20 cm
$ω$ = 10π rad/s
$\begin{array}{l} E = \frac{1}{2} {BωR}^{2} \\ = 0.2512 V \end{array}$

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