A uniform magnetic field of 0.2×10^–2T exist in the space find the change in the magnetic scalar potential as one moves through the 50cm along the field

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decreases by 1× 10^–3 Tm

increases by 0.20 × 10^–3 Tm

increases by 0.10 × 10^–3 Tm

decreases by 0.20 × 10^–3 Tm

answer is A.

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Detailed Solution

$\begin{array}{l} B = - \frac{{dv}_{B}}{dr} \Rightarrow - △ v_{B} = B \cdot △ r \\ = 0 .2 \times 10^{- 2} \times 50 \times 10^{- 2} \\ = 10 \times 10^{- 4} = 1 \times 10^{- 3} \end{array}$

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