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A uniform magnetic field B exists along y-axis and a uniform electric field of magnitude 10⁴ V/m exists along, negative z-axis. If $a charge - 16 \times 10^{- 18} C$ charge passes through the field along x-axis with a velocity 10 m/s without any deflection. Magnitude of B is :

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$10^{3} Wb / m^{2}$

$10^{5} Wb / m^{2}$

$10^{16} Wb / m^{2}$

$10^{- 3} Wb / m^{2}$

answer is A.

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Detailed Solution

As per question $\vec{B}$ is perpendicular to $\vec{E}$ and charge is moving undeflected, so magnetic force should be equal to electric force, i.e, qE = qvB

$\Rightarrow E = v B$

$\Rightarrow B = \frac{E}{v} = \frac{10^{4} v / m}{10 m / s} = 10^{3} Wb / m^{2}$

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