A uniform magnetic field$-{\mathrm{B}}_0\hat{\mathrm{k}}$ exists to the right of the plane y
x tan$\mathrm{\theta }$ as shown. At t = 0 a particle of mass m and positive charge q with velocity ${\mathrm{v}}_0\hat{\mathrm{i}}$ enters in magnetic field at origin. Then

particle will come out from magnetic field after $\mathrm{t}=\frac{\mathrm{\theta m}}{{\mathrm{qB}}_0}$

particle will come out from magnetic field after time $\mathrm{t}=\frac{2\theta \mathrm{m}}{{\mathrm{qB}}_0}$

Co-ordinate of point from which particle will come out is $\left[\frac{{\mathrm{mv}}_0}{{\mathrm{q}}_{\mathrm{B}}}\sin 2\mathrm{\theta },\frac{{\mathrm{mv}}_0}{{\mathrm{qB}}_0}(1-\cos 2\mathrm{\theta }),0\right]$

Co-ordinate of point from which particle will come is $\left[\frac{{\mathrm{mv}}_0}{{\mathrm{qB}}_0}\sin \mathrm{\theta },\frac{{\mathrm{mv}}_0}{{\mathrm{qB}}_0}(1-\cos \mathrm{\theta }),0\right]$