A uniform metal coin of mass 5 g and radius 1 cm fixed to a thin stick AB of negligible mass as shown in the figure. The system is initially at rest. The constant torque about AB, that will make the system to rotate about AB at an angular speed of 25 revolutions per second in 5s, is close to:

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$7.9 \times 10^{- 6} N m$

$2.0 \times 10^{- 5} N m$

$4.0 \times 10^{- 6} N m$

$1.6 \times 10^{- 5} N m$

answer is C.

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Detailed Solution

$α = \frac{d ω}{d t} = 10 π τ = I α = \frac{5}{4} (M R^{2}) α = 2 \times 10^{- 5} N - m$

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